Consider \(n\) consecutive positive integers.
Can we divide them into two groups so that the sum
of the numbers in each group is a prime number if
(A) \(n = 8\), (B) \(n = 10\)?
Each group must contain at least \(2\) numbers.
Apskatām \(n\) pēc kārtas ņemtus naturālus skaitļus.
Vai var gadīties, ka tos var sadalīt divās grupās tā, ka katras
grupas skaitļu summa ir pirmskaitlis, ja (A) \(n = 8\),
(B) \(n = 10\)? Katrā grupā jābūt vismaz \(2\) skaitļiem.